2y^2+3y-5=4

Solution for 2y^2+3y-5=4 equation:

Simplifying
2y2 + 3y + -5 = 4

Reorder the terms:
-5 + 3y + 2y2 = 4

Solving
-5 + 3y + 2y2 = 4

Solving for variable 'y'.

Reorder the terms:
-5 + -4 + 3y + 2y2 = 4 + -4

Combine like terms: -5 + -4 = -9
-9 + 3y + 2y2 = 4 + -4

Combine like terms: 4 + -4 = 0
-9 + 3y + 2y2 = 0

Factor a trinomial.
(-3 + -1y)(3 + -2y) = 0

Subproblem 1
Set the factor '(-3 + -1y)' equal to zero and attempt to solve:

Simplifying
-3 + -1y = 0

Solving
-3 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1y = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1y = 0 + 3
-1y = 0 + 3

Combine like terms: 0 + 3 = 3
-1y = 3

Divide each side by '-1'.
y = -3

Simplifying
y = -3
Subproblem 2
Set the factor '(3 + -2y)' equal to zero and attempt to solve:

Simplifying
3 + -2y = 0

Solving
3 + -2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2y = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2y = 0 + -3
-2y = 0 + -3

Combine like terms: 0 + -3 = -3
-2y = -3

Divide each side by '-2'.
y = 1.5

Simplifying
y = 1.5
Solution
y = {-3, 1.5}